Gutter

How much metal is needed for production 60 pieces of gutter pipes with the diameter 17 cm and length of 6 m? The plate bends add 6% of the material.

Result

S =  203.8 m2

Solution:

n=60 D=17 cm→m=17/100 m=0.17 m l=6 m  q=6%=1+6100=1.06  o=π⋅ D=3.1416⋅ 0.17≐0.5341 m S1=o⋅ l=0.5341⋅ 6≐3.2044 m2  S=n⋅ S1⋅ q=60⋅ 3.2044⋅ 1.06≐203.8014≐203.8 m2n=60 \ \\ D=17 \ cm \rightarrow m=17 / 100 \ m=0.17 \ m \ \\ l=6 \ \text{m} \ \\ \ \\ q=6 \%=1 + \dfrac{ 6 }{ 100 }=1.06 \ \\ \ \\ o=\pi \cdot \ D=3.1416 \cdot \ 0.17 \doteq 0.5341 \ \text{m} \ \\ S_{1}=o \cdot \ l=0.5341 \cdot \ 6 \doteq 3.2044 \ \text{m}^2 \ \\ \ \\ S=n \cdot \ S_{1} \cdot \ q=60 \cdot \ 3.2044 \cdot \ 1.06 \doteq 203.8014 \doteq 203.8 \ \text{m}^2

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