Iron sulfide composition

How many kg of iron and how many kg of sulfur does 100 kilograms of iron sulfide (FeS) contain if the relative atomic weight of iron is 52 and sulfur 32?

Final Answer:

m₁ =  61.9 kg
m₂ =  38.1 kg

Step-by-step explanation:

$$\begin{gathered} m=100\text{kg} \\ Fe:S \\ {m}_1:m_2=52:32 \\ {m}_1+m_2=m \\ d=\frac{m}{52+32}=\frac{100}{52+32}=\frac{25}{21}\doteq 1.1905\text{kg} \\ {m}_1=52\cdot d=52\cdot \frac{25}{21}=\frac{52\cdot 25}{21}=\frac{1300}{21}=\frac{1300}{21}\text{kg}=61.9\text{kg} \end{gathered}$$

$m_2=32\cdot d=32\cdot \frac{25}{21}=\frac{32\cdot 25}{21}=\frac{800}{21}=38.1\text{kg}$

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