Paul earned

Paul earned 300 CZK in one hour, Wesley 1/3 more than Paul. Wesley worked 60 hours, which is 1/3 fewer hours than Paul worked. How much percent less did Paul an hour than Wesley? How many hours did Paul more than Wesley? How much did Paul earn more than Wesley?

Final Answer:

a =  25 %
b =  30 h
c =  12.5 %

Step-by-step explanation:

p=300 Kc/h v=p+p/3=300+300/3=400 Kc/h  h2​=60 h h2​ = h1​−h1​/3 h1​=h2​/(1−31​)=60/(1−31​)=90 h  a=100⋅ vv−p​=100⋅ 400400−300​=25%
b=h1​−h2​=90−60=30 h
z1​=p⋅ h1​=300⋅ 90=27000 Kc z2​=v⋅ h2​=400⋅ 60=24000 Kc  c=100⋅ z2​z1​−z2​​=100⋅ 2400027000−24000​=225​%=12.5%

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You need to know the following knowledge to solve this word math problem:

algebrabasic operations and conceptsnumbersUnits of physical quantitiesthemes, topicsGrade of the word problem

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