# Area of a triangle

What is the area of a triangle that has the base 4 1/4 and the height of 3 3/3?

Result

A =  8.5

#### Solution:

$a=4 + \dfrac{ 1 }{ 4 }=\dfrac{ 17 }{ 4 }=4.25 \ \\ h=3 + \dfrac{ 3 }{ 3 }=4 \ \\ \ \\ A=\dfrac{ a \cdot \ h }{ 2 }=\dfrac{ 4.25 \cdot \ 4 }{ 2 }=\dfrac{ 17 }{ 2 }=8.5$

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