Passenger 64534

A passenger car drove a highway section at a constant speed. At a speed of 20 km/h higher, the ride would take 6 minutes less. At a speed of 20 km/h lower, it would take 9 minutes more. Calculate the length of the highway section.

Correct answer:

x =  60 km

Step-by-step explanation:

Δ=20 km/h t1=6 min h=6:60  h=0.1 h t2=9 min h=9:60  h=0.15 h  x = v t x = (v+Δ) (tt1) x = (vΔ) (t+t2)  v t = (v+Δ) (tt1) v t = (vΔ) (t+t2)  v t = vt+Δt t1v t1Δ v t = vtΔt +t2v t2Δ  0=Δ tt1 vt1 Δ 0=Δ t+t2 vt2 Δ 0=20 t0.1 v0.1 20 0=20 t+0.15 v0.15 20  20t0.1v=2 20t0.15v=3  Row2Row1Row2 20t0.1v=2 0.05v=5  v=0.055=100 t=202+0.1v=202+0.1 100=0.6  t=53=0.6 v=100  x=v t=100 0.6=60 km   Verifying Solution:   v2=v+Δ=100+20=120 km/h v3=vΔ=10020=80 km/h  s1=v t=100 0.6=60 km s2=v2 (tt1)=120 (0.60.1)=60 km s3=v3 (t+t2)=80 (0.6+0.15)=60 km



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