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The cyclist in the 1st stage covered 70 km at a speed of 22.1 km/h. In the 2nd stage, he covered 40 km (a total of 110 km), and his average speed increased to 22.9 km/h. What an average speed he developed in the 2nd stage.

Correct answer:

v2 =  24.4488 km/h

Step-by-step explanation:

v1=22.1 km/h s1=70 km  s2=40 km v=22.9 km/h  t1=s1/v1=70/22.1=2217003.1674 h t=(s1+s2)/v=(70+40)/22.9=22911004.8035 h t2=tt1=4.80353.16741.6361 h  v2=s2/t2=40/1.6361=24.4488 km/h



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