Intercept with axis

F(x)=log(x+4)-2, what is the x intercept

Result

x =  96

Solution:

F(x)=log⁡(x+4)−2 F(x)=0 log⁡(x+4)−2=0 log⁡(x+4)=2 x+4=102 x=102−4=96F(x)=\log(x+4)-2 \ \\ F(x)=0 \ \\ \log(x+4)-2=0 \ \\ \log(x+4)=2 \ \\ x+4=10^2 \ \\ x=10^2 - 4=96

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Dr Math
Assuming "log" is the decadic logarithm (log with base 10)

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