The bulb

Calculate what voltage is at the terminals of the bulb, if the work is done 18 J to transfer particles with an electric charge of 6 C.

Correct result:

U =  3 V

Solution:

$$\begin{gathered} W=18\text{ J } \\ Q=6\text{ C } \\ Q=It \\ W=UIt=UQ \\ U=W\mathrm{/}Q=18\mathrm{/}6=3\text{ V} \end{gathered}$$

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