Cancer in woman population

In a particular population of women, 40% have had breast cancer, 20% are smokers, and 13% are smokers and have had breast cancer. If a woman is selected at random from the population, what is the probability that she has breast cancer, smokes, or both?

Correct answer:

p =  47 %

Step-by-step explanation:

p1=40 % p2=20 % p3=13 %  P(AB) = P(A)+P(B)P(AB)  p=p1+p2p3=40+2013=47%

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