Sum of inner angles

Prove that the sum of all inner angles of any convex n-angle equals (n-2) . 180 degrees.

Result

d =  0

Solution:

n=3...s3=180∘ n=4...s4=s3+180∘ n=5...s5=s4+180∘ s=180n−360=180(n−2) d=0n=3 ... s_{ 3 }=180^\circ \ \\ n=4 ... s_{ 4 }=s_{ 3 } + 180^\circ \ \\ n=5 ... s_{ 5 }=s_{ 4 } + 180^\circ \ \\ s=180n - 360=180(n-2) \ \\ d=0

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