# Is right-angled

Can a triangle with the sides of sqrt 3, sqrt 5 and sqrt 8 (√3, √5 and √8) be a right triangle?

Result

y =  1

#### Solution:

$a=\sqrt{ 3 }=\sqrt{ 3 } \doteq 1.7321 \ \\ b=\sqrt{ 5 }=\sqrt{ 5 } \doteq 2.2361 \ \\ c=\sqrt{ 8 }=2 \ \sqrt{ 2 } \doteq 2.8284 \ \\ \ \\ \sqrt{ x }^2=x \ \\ \ \\ a^2 + b^2=c^2 \ \\ 3 + 5=8 \ \\ y=1$

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