A trapezoid

A trapezoid 75 ft wide on top 85 ft on the bottom, the height is 120 ft. What is its area in the square yds?

Correct answer:

S =  1066.6667 yd²

Step-by-step explanation:

$$\begin{gathered} c=75\text{ ft } \\ a=85\text{ ft } \\ h=120\text{ ft } \\ {S}_1={\displaystyle \frac{a+c}{2}}\cdot h={\displaystyle \frac{85+75}{2}}\cdot 120=9600{\text{ft}}^2 \\ S=S_1\to {\text{yd}}^2=S_1\mathrm{/}9{\text{yd}}^2=9600\mathrm{/}9{\text{yd}}^2=1066.667{\text{yd}}^2={\displaystyle \frac{3200}{3}}{\text{yd}}^2=1066.6667{\text{yd}}^2 \end{gathered}$$

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