A trapezoid

A trapezoid 75 ft wide on top 85 ft on the bottom, the height is 120 ft. What is its area in the square yds?

Correct result:

S =  1066.667 yd2

Solution:

c=75 ft a=85 ft h=120 ft  S1=a+c2⋅ h=85+752⋅ 120=9600 ft2 S=S1→yd2=S1/9 yd2=9600/9 yd2=1066.667 yd2=1066.667 yd2c=75 \ \text{ft} \ \\ a=85 \ \text{ft} \ \\ h=120 \ \text{ft} \ \\ \ \\ S_{1}=\dfrac{ a+c }{ 2 } \cdot \ h=\dfrac{ 85+75 }{ 2 } \cdot \ 120=9600 \ \text{ft}^2 \ \\ S=S_{1} \rightarrow yd^2=S_{1} / 9 \ yd^2=9600 / 9 \ yd^2=1066.667 \ yd^2=1066.667 \ \text{yd}^2

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