Expressions 3

If k(x+6)= 4x2 + 20, what is k(10)=?

Correct result:

k10 =  84

Solution:

k(x+6)=4x2+20 k(x)=4(x−6)2+20  k10=4⋅ (10−6)2+20=84k(x +6)=4x^2 + 20 \ \\ k(x)=4(x-6)^2 + 20 \ \\ \ \\ k_{10}=4 \cdot \ (10-6)^2+20=84

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