# Isosceles triangle

The circumference of the isosceles triangle is 32.5 dm. Base length is 153 cm. How long is the leg of this triangle?

Result

r =  8.6 dm

#### Solution:

$o=32.5 \ \text{dm} \ \\ a=153 \ cm=153 / 10 \ dm=15.3 \ dm \ \\ \ \\ o=a + 2r \ \\ r=(o-a)/2=(32.5-15.3)/2=\dfrac{ 43 }{ 5 }=8.6 \ \text{dm}$

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