Isosceles triangle

The circumference of the isosceles triangle is 32.5 dm. Base length is 153 cm. How long is the leg of this triangle?

Correct answer:

r =  8.6 dm

Step-by-step explanation:

$$\begin{gathered} o=32.5\text{ dm } \\ a=153\text{ cm}\to \text{ dm}=153\mathrm{/}10\text{ dm}=15.3\text{ dm } \\ o=a+2r \\ r=(o-a)\mathrm{/}2=(32.5-15.3)\mathrm{/}2=8.6\text{ dm} \end{gathered}$$

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