The perimeter 2

The perimeter of the quadrilateral a = 1m b = 14/5m c = 2 3/10m d = 1 4/5m?

Correct result:

p =  7.9 m

Solution:

a=1 m b=14/5=145=2.8 m c=2+3/10=2310=2.3 m d=1+4/5=95=1.8 m  p=a+b+c+d=1+2.8+2.3+1.8=7910=7.9 ma=1 \ \text{m} \ \\ b=14/5=\dfrac{ 14 }{ 5 }=2.8 \ \text{m} \ \\ c=2 + 3/10=\dfrac{ 23 }{ 10 }=2.3 \ \text{m} \ \\ d=1 + 4/5=\dfrac{ 9 }{ 5 }=1.8 \ \text{m} \ \\ \ \\ p=a+b+c+d=1+2.8+2.3+1.8=\dfrac{ 79 }{ 10 }=7.9 \ \text{m}



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