Adam placed the ladder of the house, the upper end reaching to the window at the height of 3.6m, and the lower end standing on level ground and was distant from a wall of 1.5m. What is the length of the ladder?

Result

d =  3.9 m

#### Solution:

$a=3.6 \ \text{m} \ \\ b=1.5 \ \text{m} \ \\ \ \\ d=\sqrt{ a^2+b^2 }=\sqrt{ 3.6^2+1.5^2 }=\dfrac{ 39 }{ 10 }=3.9 \ \text{m}$

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