# Hostel

Students are accommodated in 22 rooms. Rooms were 4 and 6 bed.
How many rooms in which type occupied 106 children there?

Result

x4 =  13
x6 =  9

#### Solution:

$106=4 x+6 y \ \\ 22=x+y \ \\ \ \\ 106 = x(4-6) + 6\cdot 22 \ \\ x = \dfrac{ 106- 6\cdot 22 } { 4 - 6} = 13$
$y = 22 - x = 9$

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