Flooring a room

Find the cost of flooring a room 6.5 m by 5 m with square tiles of sides 25 cm at the rate of rupees 9.40 per tile.

Result

x =  4888 Rp

Solution:

a=6.5 m b=5 m  S1=a⋅ b=6.5⋅ 5=652=32.5 m2  c=25 cm=25/100 m=0.25 m S2=c2=0.252=116=0.0625 m2  n=S1/S2=32.5/0.0625=520  x=9.40⋅ n=9.40⋅ 520=4888 Rpa=6.5 \ \text{m} \ \\ b=5 \ \text{m} \ \\ \ \\ S_{1}=a \cdot \ b=6.5 \cdot \ 5=\dfrac{ 65 }{ 2 }=32.5 \ \text{m}^2 \ \\ \ \\ c=25 \ cm=25 / 100 \ m=0.25 \ m \ \\ S_{2}=c^2=0.25^2=\dfrac{ 1 }{ 16 }=0.0625 \ \text{m}^2 \ \\ \ \\ n=S_{1}/S_{2}=32.5/0.0625=520 \ \\ \ \\ x=9.40 \cdot \ n=9.40 \cdot \ 520=4888 \ \text{Rp}

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