# Volume of ball

Find the volume of a volleyball that has a radius of 4 1/2 decimeters. Use 22/7 for π

Result

V =  381.857 dm3

#### Solution:

$r = 4 + \dfrac{ 1 }{ 2 } = \dfrac{ 9 }{ 2 } = 4.5 \ dm \ \\ \ \\ V = \dfrac{ 4 }{ 3 } \pi r^3 \ \\ \ \\ V = \dfrac{ 4 }{ 3 } \cdot \ \dfrac{ 22 }{ 7 } \cdot \ r^3 = \dfrac{ 4 }{ 3 } \cdot \ \dfrac{ 22 }{ 7 } \cdot \ 4.5^3 = \dfrac{ 2673 }{ 7 } \doteq 381.8571 = 381.857 \ dm^3$

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