# Perfect cubes

Suppose a number is chosen at random from the set (0,1,2,3,. .. ,202).
What is the probability that the number is a perfect cube?

Result

p =  2.475 %

#### Solution:

$c_{1}=1^3 \ \\ c_{2}=2^3=8 \ \\ c_{3}=3^3=27 \ \\ c_{4}=4^3=64 \ \\ c_{5}=5^3=125 \ \\ c_{6}=6^3=216 \ \\ \ \\ 0

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