The classroom 3

The classroom needs a new floor. The dimensions of the classroom are 34 1/2 feet by 36 1/2 feet. Find the area of the classroom.

SIMPLIFY.

Correct answer:

A =  1259 ¹⁄₄ = 5037/4 ft²

Step-by-step explanation:

$$\begin{gathered} a=34\frac{1}{2}=34+\frac{1}{2}=\frac{34\cdot 2+1}{2}=\frac{68+1}{2}=\frac{69}{2}=34.5\text{ft} \\ b=36\frac{1}{2}=36+\frac{1}{2}=\frac{36\cdot 2+1}{2}=\frac{72+1}{2}=\frac{73}{2}=36.5\text{ft} \\ A=a\cdot b=\frac{69}{2}\cdot \frac{73}{2}=\frac{69\cdot 73}{2\cdot 2}=\frac{5037}{4}=\frac{5037}{4}{\text{ft}}^2=1259\frac{1}{4}{\text{ft}}^2=1259.25{\text{ft}}^2 \end{gathered}$$

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