Two gears

The gearbox will use a large gear to turn a smaller gear. The large gear will make 75 revolutions per minute. The smaller gear must make 384 revolutions per minute. Find the smallest number of teeth each gear could have. [Hint: Use either GCF or LCM. ]

Correct answer:

a =  128
b =  25

Step-by-step explanation:

s1=s2 75a = 384b  75=352 384=273 GCD(75,384)=3  k=GCD(75,384)=3  a=384/k=384/3=128

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