A large

A large gear will be used to turn a smaller gear. The large gear will make 75 revolutions per minute. The smaller gear must make 384 revolutions per minute. Find the smallest number of teeth each gear could have. [Hint: Use either GCF or LCM. ]

Correct result:

a =  128
b =  25

Solution:

s1=s2 75a=384b  75=352 384=273 GCD(75,384)=3  k=GCD(75,384)=3  a=384/k=384/3=128
b=75/k=75/3=25



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