Hectoliters of water

The pool has a total of 126 hectoliters of water. The first pump draws 2.1 liters of water per second. A second pump pumps 3.5 liters of water per second.

How long will it take both pumps to drain four-fifths of the water at the same time?

Result

t =  1800 s

Solution:

V=126 hl=126 100 l=12600 l Q=2.1+3.5=5.6 l/s  V2=45 V=45 12600=10080 l  t=V2/Q=10080/5.6=1800=1800  s V = 126 \ hl = 126 \cdot \ 100 \ l = 12600 \ l \ \\ Q = 2.1 + 3.5 = 5.6 \ l/s \ \\ \ \\ V_{ 2 } = \dfrac{ 4 }{ 5 } \cdot \ V = \dfrac{ 4 }{ 5 } \cdot \ 12600 = 10080 \ l \ \\ \ \\ t = V_{ 2 }/Q = 10080/5.6 = 1800 = 1800 \ \text{ s }



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