Hectoliters of water

The pool has a total of 126 hectoliters of water. The first pump draws 2.1 liters of water per second. A second pump pumps 3.5 liters of water per second.

How long will it take both pumps to drain four-fifths of the water at the same time?

Correct result:

t =  1800 s

Solution:

V=126 hll=126 100 l=12600 l Q=2.1+3.5=5.6 l/s  V2=45 V=45 12600=10080 l  t=V2/Q=10080/5.6=1800 sV=126 \ hl \rightarrow l=126 \cdot \ 100 \ l=12600 \ l \ \\ Q=2.1 + 3.5=5.6 \ \text{l/s} \ \\ \ \\ V_{2}=\dfrac{ 4 }{ 5 } \cdot \ V=\dfrac{ 4 }{ 5 } \cdot \ 12600=10080 \ \text{l} \ \\ \ \\ t=V_{2}/Q=10080/5.6=1800 \ \text{s}



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