First pump flows 16 liters per second into the basin by the second pump 75% of the first and by third pump half more than the second. How long will take fill basin by all three pumps simultaneously volume 15 m3 (cubic meters)?

Correct answer:

x =  326 s

Step-by-step explanation:

a = 16
b = 0.75 • a
c = 1.5 • b
16 x + 0.75• 16 • x + (0.75• 16 •x)(1+1/2) = 15•1000

a = 16
b = 0.75 • a
c = 1.5 • b
16•x + 0.75• 16 • x + (0.75• 16 •x)•(1+1/2) = 15•1000

a = 16
0.75a-b = 0
1.5b-c = 0
92x = 30000

a = 16
b = 12
c = 18
x = 7500/23 ≈ 326.086957

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