Normally distributed

Suppose the height of male youngsters is normally distributed with a mean of 60 inches and a standard deviation of 10. what percentage of the boy's height would we expect to be between 44 and 75, less than 49, and 76 and more?

Correct answer:

p1 =  87.84 %
p2 =  13.57 %
p3 =  5.48 %

Step-by-step explanation:

m=60 in σ=10 in  p1 = N(44<x<75) p1=100 0.8784=87.84%

Use the normal distribution table.
p2 = N(x<49) p2=100 0.1357=13.57%

Use the normal distribution table.
p3 = N(x>76) p3=100 0.0548=5.48%

Use the normal distribution table.

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