# Mixing Celsius and Fahrenheit

5°F +6°F +0°C

Result

t1 =  43 °F
t2 =  -11.667 °C

#### Solution:

$(F-32) \cdot \ \dfrac{ 5 }{ 9 } = C \ \\ t_{ 1 } = 5 +6 +(0 \cdot \ \dfrac{ 9 }{ 5 } +32) = 43 = 43 ^\circ F$
$t_{ 2 } = (5+6-32) \cdot \ \dfrac{ 5 }{ 9 } + 0 = - \dfrac{ 35 }{ 3 } \doteq -11.6667 = -11.667 ^\circ C$

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Showing 1 comment:
Math student
Hi
The above solution is incorrect as 0 degree Celsius is 32 degree Fahrenheit. Hence, the answer is 5 degree F + 6 degree F + 32 degree F = 43 degree F

Thank you

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