Water + temperature

We supplied 1365 kJ of heat to water weighing 5 kg and initially at 20°C. To what temperature did it heat up?

Correct answer:

t2 =  85 °C

Step-by-step explanation:

t1=20 °C m=5 kg Q=1365 kJ c=4.2 kJ/°C/kg  Q = m c (t2t1)  t2=t1+m cQ=20+5 4.21365=85°C



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