Water + temperature

We supplied 1,365 kJ of heat to 5 kg of water initially at 20 °C. To what temperature did it heat up?

Final Answer:

t2 =  85 °C

Step-by-step explanation:

t1=20 °C m=5 kg Q=1365 kJ c=4.2 kJ/°C/kg  Q = m c (t2t1)  t2=t1+m cQ=20+5 4.21365=85°C



Help us improve! If you spot a mistake, please let let us know. Thank you!







Tips for related online calculators
Do you want to convert time units like minutes to seconds?

You need to know the following knowledge to solve this word math problem:

Related math problems and questions: