Latent heat

How much heat is needed to take from 100 g of water at 20°C to cool to the ice at -18°C? Mass heat capacity c (ice) = 21kJ/kg/°C; c (water) = 4.19 KJ/kg/°C and the mass group heat of solidification of water is l = 334kJ/kg

Correct answer:

Q =  45.56 kJ

Step-by-step explanation:

m=100 g kg=100:1000  kg=0.1 kg t1=20 °C t2=0 °C t3=18 °C  c1=2.1 kJ/kg/°C c2=4.19 kJ/kg/°C l=334 kJ/kg  Q1=m c2 (t1t2)=0.1 4.19 (200)=50419=8.38 kJ Q2=m l=0.1 334=5167=33.4 kJ Q3=m c1 (t2t3)=0.1 2.1 (0(18))=50189=3.78 kJ  Q=Q1+Q2+Q3=8.38+33.4+3.78=45.56 kJ

Did you find an error or inaccuracy? Feel free to write us. Thank you!

Showing 1 comment:
Sam Morrow
It doesn’t work for me

Tips for related online calculators
Do you want to convert mass units?

You need to know the following knowledge to solve this word math problem:

Related math problems and questions: