Five-digit number count

Determine the number of all natural numbers greater than 2000 in which the digits 1, 2, 4, 6, and 8 occur at most once each.

Final Answer:

n =  216

Step-by-step explanation:

n=4 4 3 2+5 4 3 2 1=216



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combinatoricsarithmeticbasic operations and conceptsnumbersGrade of the word problem

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