Natural numbers

Determine the number of all natural numbers greater than 200 in which the digits 1, 2, 4, 6, and 8 occur at most once each.

Correct answer:

n =  288

Step-by-step explanation:

a=4 4 3=48 b=5 4 3 2=120 c=5 4 3 2 1=120  n=a+b+c=48+120+120=288



Did you find an error or inaccuracy? Feel free to write us. Thank you!



Showing 2 comments:
Student
In this question can I get some more explanation pls.

2 months ago  2 Likes
Math student
This is wrong (or the question is written poorly). There are infinite such numbers:

12468
124680
1246800
etc...





Tips for related online calculators
See also our permutations calculator.
See also our variations calculator.
Would you like to compute the count of combinations?

You need to know the following knowledge to solve this word math problem:

Related math problems and questions: