Consecutive 8032

Find three consecutive numbers whose sum is 630,000.

Correct answer:

a =  209999
b =  210000
c =  210001

Step-by-step explanation:


a+(a+1)+(a+2)=630000

3a = 629997


a = 629997/3 = 209999

a = 209999

Our simple equation calculator calculates it.
b=a+1=209999+1=210000
c=b+1=210000+1=210001



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