Find two

Find two consecutive natural numbers whose product is one larger than their sum. Searched numbers are expressed by a fraction whose numerator is the difference between these numbers, and the denominator is their sum.

Correct answer:

a =  2
b =  3

Step-by-step explanation:

b = a+1 ab = 1+ (a+b) a (a+1)=1+(a+(a+1))  a (a+1)=1+(a+(a+1)) a2a2=0  p=1;q=1;r=2 D=q24pr=1241(2)=9 D>0  a1,2=2pq±D=21±9 a1,2=21±3 a1,2=0.5±1.5 a1=2 a2=1  a>0 a=a1=2

Our quadratic equation calculator calculates it.

b=a+1=2+1=3   Verifying Solution:  s1=a b=2 3=6 s2=a+b=2+3=5 s1 = 1+s2

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