Find two

Find two consecutive natural numbers whose product is 1 larger than their sum. Searched numbers expressed by a fraction whose numerator is the difference between these numbers and the denominator is their sum.

Correct result:

a =  2
b =  3

Solution:

b=a+1 ab=1+(a+b) a(a+1)=1+(a+(a+1))  a (a+1)=1+(a+(a+1)) a2a2=0  p=1;q=1;r=2 D=q24pr=1241(2)=9 D>0  a1,2=q±D2p=1±92 a1,2=1±32 a1,2=0.5±1.5 a1=2 a2=1   Factored form of the equation:  (a2)(a+1)=0  a>0 a=a1=2

Our quadratic equation calculator calculates it.

b=a+1=2+1=3b=a+1=2+1=3



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