Find two

Find two consecutive natural numbers whose product is one larger than their sum. Searched numbers are expressed by a fraction whose numerator is the difference between these numbers, and the denominator is their sum.

Correct answer:

a =  2
b =  3

Step-by-step explanation:

b=a+1 ab=1+(a+b) a(a+1)=1+(a+(a+1))  a (a+1)=1+(a+(a+1)) a2a2=0  p=1;q=1;r=2 D=q24pr=1241(2)=9 D>0  a1,2=2pq±D=21±9 a1,2=21±3 a1,2=0.5±1.5 a1=2 a2=1   Factored form of the equation:  (a2)(a+1)=0  a>0 a=a1=2

Our quadratic equation calculator calculates it.

b=a+1=2+1=3   Verifying Solution:  s1=a b=2 3=6 s2=a+b=2+3=5 s1=1+s2



Did you find an error or inaccuracy? Feel free to write us. Thank you!







Tips for related online calculators
Are you looking for help with calculating roots of a quadratic equation?
Do you have a linear equation or system of equations and looking for its solution? Or do you have a quadratic equation?

You need to know the following knowledge to solve this word math problem:

Related math problems and questions: