Probability 80560

I have 3 sources, and their failure probability is 0.1. Calculate the probability that:
a) none will have a malfunction
b) 1 will have a breakdown
c) at least 1 will have a fault
d) they will all have a breakdown

Correct answer:

a =  0.729
b =  0.243
c =  0.271
d =  0.001

Step-by-step explanation:

p=0.1 n=3  a=(0n)p0(1p)n0=(03)0.10(10.1)30=10.100.93=0.729
b=(1n)p1(1p)n1=(13)0.11(10.1)31=30.110.92=0.243
c=1a=10.729=0.271
d=(nn)pn(1p)nn=(33)0.13(10.1)33=10.130.90=0.001



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