Bernoulli trial

A used car saleswoman estimates that each time she shows a customer a car, there is a probability of 0.1 that the customer will buy the car. The saleswoman would like to sell at least one car per week. If showing a car is a Bernoulli trial with a probability of 0.95 of at least one sale,
(i) how many cars would the saleswoman show per week?
(ii) calculate the probability of exactly three sales per week.

Correct answer:

n =  29
p3 =  0.2361

Step-by-step explanation:

k=0.1 p0=1k=10.1=109=0.9  1p0n = 0.95 p0n = 0.05  n ln p0 = ln 0.05  n0=ln(p0)ln0.05=ln0.9ln0.0528.4332  n=n0=28.4332=29
p3=(3n)k3(1k)n3=(329)0.13(10.1)293=36540.130.926=0.2361



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statisticscombinatoricsarithmeticbasic operations and conceptsGrade of the word problem

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