A transmitter tower

A transmitter tower is 80 meters high and is stabilized to the ground by 4 steel cables anchored in the ground 60 meters from the base of the tower.
Calculate how many meters of steel cable were needed to stabilize the transmitter tower.
The steel cable used has a circular cross-section with a radius of 2 cm. Calculate how much steel was used to produce 1 km of cable. Express the result in m³ and round to 2 decimal places.

Final Answer:

x =  400 m
V =  1.26 m³

Step-by-step explanation:

$$\begin{gathered} n=4 \\ a=80\text{m} \\ b=60\text{m} \\ {x}_1=\sqrt{a^2+b^2}=\sqrt{80^2+60^2}=100\text{m} \\ x=n\cdot x_1=4\cdot 100=400\text{m} \end{gathered}$$

$$\begin{gathered} r=2\text{cm}\to \text{m}=2:100\text{m}=0.02\text{m} \\ l=1\text{km}\to \text{m}=1\cdot 1000\text{m}=1000\text{m} \\ V=\pi \cdot r^2\cdot l=3.1416\cdot 0.02^2\cdot 1000=1.26{\text{m}}^3 \end{gathered}$$

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