Water tank

A cuboid-shaped water tank has a base measuring 7.5 metres by 3 metres. How high will the water reach if 10 litres of water flow in per second and the inlet is open for 5/6 of an hour?
(Round the result to one decimal place and express it in metres.)

Final Answer:

h =  1.3 m

Step-by-step explanation:

$$\begin{gathered} a=7.5\text{m} \\ b=3\text{m} \\ Q=10\text{l/s} \\ t=5/6=\frac{5}{6}\doteq 0.8333\text{h} \\ S=a\cdot b=7.5\cdot 3=\frac{45}{2}=22.5{\text{m}}^2 \\ {t}_1=t\to \text{s}=t\cdot 3600\text{s}=0.8333\cdot 3600\text{s}=3000\text{s} \\ V=Q\cdot t_1=10\cdot 3000=30000\text{l} \\ {V}_1=V\to {\text{m}}^3=V:1000{\text{m}}^3=30000:1000{\text{m}}^3=30{\text{m}}^3 \\ V=S\cdot h \\ h=V_1/S=30/22.5=1.3\text{m} \end{gathered}$$

Try another example