Water tank

What is the height of the cuboid-shaped tank with the bottom dimensions of 80 cm and 50 cm if the 480 liters of water reaches 10 cm below the top?

Result

c =  130 cm

Solution:

V=480 l→cm3=480⋅ 1000 cm3=480000 cm3 a=80 cm b=50 cm  S1=a⋅ b=80⋅ 50=4000 cm2  c1=V/S1=480000/4000=120 cm c2=10 cm  c=c1+c2=120+10=130 cmV=480 \ l \rightarrow cm^3=480 \cdot \ 1000 \ cm^3=480000 \ cm^3 \ \\ a=80 \ \text{cm} \ \\ b=50 \ \text{cm} \ \\ \ \\ S_{1}=a \cdot \ b=80 \cdot \ 50=4000 \ \text{cm}^2 \ \\ \ \\ c_{1}=V/S_{1}=480000/4000=120 \ \text{cm} \ \\ c_{2}=10 \ \text{cm} \ \\ \ \\ c=c_{1}+c_{2}=120+10=130 \ \text{cm}

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