Tank water remaining

They drained the water from the full tank through three holes. 1/6 of the tank volume flowed through the first hole, 2/5 of the volume through the second hole, and 1/4 of the volume through the third hole. The tank has the shape of a cuboid with dimensions of 6.6 m, 3 m, and 2 m. How many liters of water are left in the tank?

Final Answer:

x =  7260 l

Step-by-step explanation:

$$\begin{gathered} a=6.6\text{m} \\ b=3\text{m} \\ c=2\text{m} \\ V=a\cdot b\cdot c=6.6\cdot 3\cdot 2=\frac{198}{5}=39.6{\text{m}}^3 \\ {V}_1=V/6=\frac{198}{5}/6=\frac{198}{5\cdot 6}=\frac{198}{30}=\frac{33}{5}=6.6{\text{m}}^3 \\ {V}_2=\frac{2}{5}\cdot V=\frac{2}{5}\cdot \frac{198}{5}=\frac{2\cdot 198}{5\cdot 5}=\frac{396}{25}=15.84{\text{m}}^3 \\ {V}_3=V/4=\frac{198}{5}/4=\frac{198}{5\cdot 4}=\frac{198}{20}=\frac{99}{10}=9.9{\text{m}}^3 \\ {V}_4=V-V_1-V_2-V_3=\frac{198}{5}-\frac{33}{5}-\frac{396}{25}-\frac{99}{10}=\frac{1980}{50}-\frac{330}{50}-\frac{792}{50}-\frac{495}{50}=\frac{1980-330-792-495}{50}=\frac{363}{50}=7.26{\text{m}}^3 \\ x=V_4\to \text{l}=V_4\cdot 1000\text{l}=7.26\cdot 1000\text{l}=7260\text{l}=7260\text{l} \end{gathered}$$

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