One in eight containers is temporarily misplaced. A random sample of 12 containers is selected. What is the probability that 6 of these containers will be temporarily misplaced?

Correct answer:

p =  0.0016

Step-by-step explanation:

p0=81=0.125  p=(612)p06(1p0)126=(612)0.1256(10.125)126=9240.12560.8756=0.0016

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