Cooker efficiency testing

When testing the effectiveness of an electric cooker with data of 220 V, 1200 W, 1 kg of water at a temperature of 15 degrees Celsius was boiled for 8.5 minutes. Calculate the stove efficiency corresponding to these data

Final Answer:

e =  0.5833

Step-by-step explanation:

U=220 V P=1200 W  m=1 kg t1=15 °C t2=100 °C t=8.5 min s=8.5 60  s=510 s c=4200 J/kg/K  Q1=P t=1200 510=612000 J Δt=t2t1=10015=85 K  Q2=m c Δt=1 4200 85=357000 J  e=Q1Q2=612000357000=0.5833



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