Calorimetric equation

A 200 g aluminium cylinder at 180 °C was dropped into 3 kg of water at 25 °C. At what temperature did the mixture stabilise? The specific heat capacity of water is 4,200 J/(kg·°C) and of aluminium is 896 J/(kg·°C).

Final Answer:

t =  27.17 °C

Step-by-step explanation:

m1=3 kg t1=25 °C c1=4200 J/kg/°C  m2=200 g kg=200:1000  kg=0.2 kg t2=180 °C c2=896 J/kg/°C  Q1=Q2  m1 c1 (tt1)=m2 c2 (t2t) 3 4200 (t25)=0.2 896 (180t)  12779.2t=347256  t=12779.2347256=27.17353199  t=27.173532=27.17°C



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