Trapezoid 52

Trapezoid perimeter = 39a-7. Three sides have the following length: 9a, 5a+1, and 17a-6. What is the length of the fourth side?

Correct answer:

D = 8a-2

Step-by-step explanation:

p=39a7 p=A+B+C+D A=9a B=5a+1 C=17a6  39a7 = 9a+5a+1+17a6+D 39a7 = 14a+17a5+D 39a7 = 31a5+D 8a2= D  D=8a2

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