Rocket start

The body launched vertically up returns to the start site in 6 seconds. What height did it have?

Correct result:

h =  44.15 m

Solution:

g=9.81 m/s2 t=6 s  t1=t/2=6/2=3 s  h=12⋅ g⋅ t12=12⋅ 9.81⋅ 32=8829200=44 29200=8829200 m=44.15 m

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