Rocket start

The body launched vertically up returns to the start site in 6 seconds. What height did it have?

Correct answer:

h =  44.15 m

Step-by-step explanation:

$$\begin{gathered} g=9.81{\text{m/s}}^2 \\ t=6\text{ s } \\ {t}_1=t\mathrm{/}2=6\mathrm{/}2=3\text{ s } \\ h={\displaystyle \frac{1}{2}}\cdot g\cdot t_1^2={\displaystyle \frac{1}{2}}\cdot 9.81\cdot 3^2={\displaystyle \frac{8829}{200}}={\displaystyle \frac{8829}{200}}\text{ m}=44.15\text{ m} \end{gathered}$$

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