The body was thrown vertically upward at speed v0 = 79 m/s. Body height versus time describe equation
h=v0t1210t2h = v0 \cdot t - \dfrac{1}{2} \cdot 10 \cdot t2
. What is the maximum height body reach?

Correct result:

h =  312.1 m


h=7910t=0 t=7.9s  hmax=797.912107.92=312.1 m h' = 79 - 10 \cdot t = 0 \ \\ t= 7.9 s \ \\ \ \\ h_{ max} = 79 \cdot 7.9 - \dfrac{1}{2} \cdot 10 \cdot 7.9^2 = 312.1 \ \text{m}

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