From the top of the 80m high tower, the body is thrown horizontally with an initial speed of 15 m/s. At what time and at what distance from the foot of the tower does the body hit the horizontal surface of the Earth? (use g = 10 ms-2)

Correct answer:

t =  4 s
x =  60 m

Step-by-step explanation:

h=80 m g=10 m/s2 v0=15 m/s  h=12 gt2  t=2 h/g=2 80/10=4 s
x=v0 t=15 4=60 m

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