Bomber

The aircraft flies at an altitude of 4100 m above the ground at speed 777 km/h. At what horizontal distance from the point B should be release any body from the aircraft body to fall into point B? (g = 9.81 m/s2)

Correct result:

x =  6240 m

Solution:

v=777 km/h=215.833 m/s h=12gt2 t=2hg t=241009.81=28.91 s x=vt=v2hg x=777/3.6241009.81 x=6240 m



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