The aircraft flies at an altitude of 4100 m above the ground at speed 777 km/h. At what horizontal distance from the point B should be release any body from the aircraft body to fall into point B? (g = 9.81 m/s2)

Correct answer:

x =  6240 m

Step-by-step explanation:

v=777 km/h=215.833 m/s h=21gt2 t=g2h t=9.8124100=28.91 s x=vt=vg2h x=777/3.69.8124100 x=6240 m

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