AMSL and skiing

Tomas skis from point A (3200m above sea level to place B. Hill has 20% descent. The horizontal distance between the start and finish is 2,5km. At what altitude is point B?

Result

B =  2700 m AMSL

Solution:

A=3200 m p=20%=20100=0.2 x=2.5 km=2.5⋅ 1000 m=2500 m  B=A−p⋅ x=3200−0.2⋅ 2500=2700=2700  m AMSL A = 3200 \ m \ \\ p = 20 \% = \dfrac{ 20 }{ 100 } = 0.2 \ \\ x = 2.5 \ km = 2.5 \cdot \ 1000 \ m = 2500 \ m \ \\ \ \\ B = A - p \cdot \ x = 3200 - 0.2 \cdot \ 2500 = 2700 = 2700 \ \text{ m AMSL }

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