Beetle cabbage pursuit

Theodore the beetle set off from the house towards the cabbage leaf at a 20 m/min speed. Two minutes later, Max the beetle followed him at 24 m/min speed. They both came to the cabbage leaf at the same time. How far was the cabbage leaf from their house?

Final Answer:

x =  240 m

Step-by-step explanation:

$$\begin{gathered} v_1=20\text{m/min} \\ {v}_2=24\text{m/min} \\ \Delta =2\text{min} \\ x=x_1=x_2 \\ {v}_1\cdot t=v_2\cdot (t-\Delta ) \\ 20\cdot t=24\cdot (t-2) \\ 4t=48 \\ t=\frac{48}{4}=12 \\ t=12 \\ x=v_1\cdot t=20\cdot 12=240 \\ \text{ Verifying Solution: } \\ {x}_2=v_2\cdot (t-\Delta )=24\cdot (12-2)=240\text{m} \end{gathered}$$

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