Snail ant meeting

A snail emerges from the leaf at a speed of 1 cm/min. At the same time, an ant rushes towards it from the stone at a speed of 5 cm/min. The distance between the leaf and the stone is 1.2 meters. How soon will they meet, and at what distance?

Final Answer:

t =  20 min
s₁ =  20 cm
s₂ =  100 cm

Step-by-step explanation:

$$\begin{gathered} v_1=1\text{cm/min} \\ {v}_2=5\text{cm/min} \\ s=1.2\text{m}\to \text{cm}=1.2\cdot 100\text{cm}=120\text{cm} \\ {v}_1\cdot t+v_2\cdot t=s \\ 1\cdot t+5\cdot t=120 \\ 6t=120 \\ t=\frac{120}{6}=20 \\ t=20=20\text{min} \end{gathered}$$

$s_1=v_1\cdot t=1\cdot 20=20\text{cm}$

$s_2=v_2\cdot t=5\cdot 20=100\text{cm}$

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