Wind drift

The plane flies at 860 km/h, passing distance 3000 kilometers with the wind and once again against the wind for 6 h 59 min. What is the wind speed?

Result

v =  31 km/h

Solution:

t1+t2=6+5960 (860+v)t1=3000 (860v)t2=3000  v=31 km/h t_1 + t_2 = 6+ \dfrac{ 59}{60} \ \\ (860+v)t_1 = 3000 \ \\ (860-v)t_2 = 3000 \ \\ \ \\ v = 31 \ \text{km/h} \ \\



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